02 Jun 07
1 edit
Originally posted by Palynka) ( = ( ) This is my guess. The space in between the brackets stands for an infinite amount, since there is nothing in between to determine an actual number, it could be anything zero to infinity. A very interesting idea palynka, even though it was probably meant to be a wise crack about the thread posters' intelligence 😉
Here's the next question:
How many superintelligent people are in this thread? Display the answer by moving one of the brackets.
) (
02 Jun 07
2 edits
XXIII
------ = II
VII
Well, if it's the same idea as the last, then move I from the XXIII and place it horizontally over the II on the right to make:
22/7 = pi
I heard this one from a friend. Move two matches to make the cow face the other direction.
http://s117.photobucket.com/albums/o51/Jirakon/?action=view¤t=Cow.png
02 Jun 07
Originally posted by JirakonAlso clever, but not strictly correct. 22/7 is slightly larger than pi.
XXIII
------ = II
VII
Well, if it's the same idea as the last, then move I from the XXIII and place it horizontally over the II on the right to make:
22/7 = pi
I heard this one from a friend. Move two matches to make the cow face the other direction.
http://s117.photobucket.com/albums/o51/Jirakon/?action=view¤t=Cow.png
http://en.wikipedia.org/wiki/Proof_that_22_over_7_exceeds_%CF%80
02 Jun 07
Originally posted by AThousandYoungHaha, I love how there's a Wikipedia article prrof about that. Well, I guees you beat the system, 22/7 += pie was what the answer was, but apparently that's wrong. Ah well.
Also clever, but not strictly correct. 22/7 is slightly larger than pi.
http://en.wikipedia.org/wiki/Proof_that_22_over_7_exceeds_%CF%80
Next question(really, quite an interesting one, and if you know the answer already don't spoil it!):
A truck travels 15 mph for the first half of the distance of a trip. How fast must it travel in the second half of the distance in order to average 30 mph for the total trip?
02 Jun 07
2 edits
Originally posted by abejnoodThose are fun problems to solve. I'll give it a go, but I'll PM you the answer since I think it's a problem for algebra students and I'm past that.
Haha, I love how there's a Wikipedia article prrof about that. Well, I guees you beat the system, 22/7 += pie was what the answer was, but apparently that's wrong. Ah well.
Next question(really, quite an interesting one, and if you know the answer already don't spoil it!):
A truck travels 15 mph for the first half of the distance of a trip. How fast ...[text shortened]... t it travel in the second half of the distance in order to average 30 mph for the total trip?
EDIT - It's harder than it looks. Still working on it.
EDIT2 - I'm too impatient. I give up for now. I'll probably look at it later.
02 Jun 07
1 edit
Originally posted by abejnoodInfinitely fast. To bring the average speed up to 30mph it would need to complete the rest of the journey in no time.
Next question(really, quite an interesting one, and if you know the answer already don't spoil it!):
A truck travels 15 mph for the first half of the distance of a trip. How fast must it travel in the second half of the distance in order to average 30 mph for the total trip?
Simple example, if the journey is 30 miles, then the first half of the distance (15 miles) will have taken an hour at 15mph. You need to cover the full 30 miles in that hour to average 30mph, so you need to teleport from there to the finish (without wasting even a few seconds saying "Beam me up Scotty"😉.
Generalised proof. Let X = distance travelled in miles , T = time taken for first half, in hours, U = time taken for second half, in hours.
First half journey, distance = average speed x time: X/2 = 15T implies X = 30T
Full journey, distance = average speed x time: X = 30 (T + U) = 30T + 30 U
To summarise X = 30T and X = 30T + 30U. Hence U = 0.