Posers and Puzzles
25 Jan 03
30 Jan 03
Originally posted by AcolyteGuys,
The answer is 50/50: note that if they both get the same number of heads, Rhymester wins.
Vaknso gets an extra toss; if he gets tails, he's at a disadvantage because he now has to get more heads than Rhymester to win; if he gets heads, he's at an advantage because (over the remaining 9 tosses each) Rhymester has to get more heads than him to win.
I think I have fairly simple explanation for it:
Every toss has probability 50%.
It does not matter how many time they toss the coin. the only condition is the total number of them must be odd.
You will find the answer more easy if you forget who tosses for how many times. It does not matter. One player can do it all and it makes no difference, because:
HEAD = I win
TAILS = you win
So, if they tos once, each has 50% to win. 3x times, because again each has 50% in every turn etc etc.
😛
30 Jan 03
Originally posted by Jiraok, how about if Vaknso tosses the coin 90 times and Rhymester 81? 😛
Guys,
I think I have fairly simple explanation for it:
Every toss has probability 50%.
It does not matter how many time they toss the coin. the only condition is the total number of them must be odd.
You will find the answer more easy if you forget who tosses for how many times. It does not matter. One player can do it all and it makes no difference, be ...[text shortened]... tos once, each has 50% to win. 3x times, because again each has 50% in every turn etc etc.
😛
