Originally posted by MIODudeIt's not hard. With four pieces there are only 64*63*62*61 positions (many are mirror images and rotations which helps) and some are not legal. You just add them up.
hey Xanthos? how do you calculate that? did you run it through Fritz or something.. curious how to do that
Originally posted by XanthosNZI believe these figures are misleading as they are based on random piece placement. With proper play, a Rook v. a Knight is usually a draw; all the inferior side need do is keep his King in the center. Unless the side with the Knight starts with his King and Knight next to each other in or near a corner, it's a draw and I would guess that would occur rarely, not almost half the time.
With the stronger side to move:
Longest Mate: 40
Wins: 48.4
Draw: 51.6
Loses: 0.0
Originally posted by no1marauderIt's not based on random placement. It's based on every placement. Every possible starting position is collated into a tablebase and the number of positions that are forced wins and draws are divided by the total number.
I believe these figures are misleading as they are based on random piece placement. With proper play, a Rook v. a Knight is usually a draw; all the inferior side need do is keep his King in the center. Unless the side with the Knight starts with his King and Knight next to each other in or near a corner, it's a draw and I would guess that would occur rarely, not almost half the time.
Where is the randomness?
Originally posted by XanthosNZAssuming that every possible starting position is equally likely, a most unrealistic assumption.
It's not based on random placement. It's based on every placement. Every possible starting position is collated into a tablebase and the number of positions that are forced wins and draws are divided by the total number.
Where is the randomness?