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Posers and Puzzles

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how many numbers in succession starting with zero can anyone do?
post you solutions
can anyone do the fist 15 or more?

+, -, x, /, (), ^, log, square roots, decimal points, factorials, double factorial, etc. are a few math symbols that can be used

Good luck!

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Originally posted by lemondrop
how many numbers in succession starting with zero can anyone do?
post you solutions
can anyone do the fist 15 or more?

+, -, x, /, (), ^, log, square roots, decimal points, factorials, double factorial, etc. are a few math symbols that can be used

Good luck!
(4+4)-(4-4)=0 that was easy...

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(4+4)-(4-4)=8
sorry ponderable

(4+4)=8
(4-4)=0
8-0=8

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4!/sqrt(4) + 4/4 = 13

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works for me
good job

4!=24
sqrt of 4=2
4/4=1
24/2=12 +4/4=1
12+1=13

anyone with a different solution?

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Now we need 11...

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11 is not that difficult
hint: use the square root function

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Originally posted by Ponderable
(4-4)*4+4=4
To be clear, it should be ((4-4)*4)+4=4

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Originally posted by forkedknight
4+(4-4)/4 = 4
4 + (4/4)^4 = 5
(4 + 4)/4 + 4 = 6
You need to get the parenthesis stuff right to be accurate, your (4+4)/4+4 could be taken as zero as it stands.

To be accurate you need (((4+4)/4)+4)=6.

or ((4+4)/4)+4=6, a bit simpler but it does come out as 6 as written, on my casio calculator.

The first example, 4+(4-4) could be taken as 4 then divide by 4 would be 1 if not clarified by parentheses, but as you wrote it, my calculator brings it out as 4.

.

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Originally posted by lemondrop
4+(4-4)/4=1 not 4
your equation for the number 5 is also incorrect
He is getting those results running it through a Casio calculator or some other brand that uses the order rules. It comes out as four running through a casio.

It still can be taken as 1 by someone not following the same order rules.

I think it should be given with proper parentheses to eliminate such confusion.

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Originally posted by forkedknight
4!/sqrt(4) + 4/4 = 13
If you do the math first, it works but I cannot enter it as shown on my casio calculator.

On my TI84 it doesn't seem to have a factorial function so I have to do it this way🙁(4*3*2)/(sqr(4))+(4/4) to get 13 which is cheating🙂

You could write a user defined program as a factorial and use that instead I guess. Surprised they didn't include factorial on the TI84.

I'll try it on my trusty rusty HP48, see what I get in reverse polish. Don't have time right now.


parentheses are absolutely necessary to avoid any ambiguity

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Originally posted by lemondrop
parentheses are absolutely necessary to avoid any ambiguity
For sure! Otherwise there can by several interpretations of the outcome.

Like 4^4+4/4, is that 257 or 65?

If you want the outcome to be 65, you go (4^4+4)/4 (4^4=256 plus 4=260 /4 =65

If you want it to be outcome to be 257 you go (4^4)+(4/4) 4^4=256 plus 4/4, (1)=257.

Everyone needs to get up to speed on this issue.

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so far we have:
0=44-44
1=44/44
2=(4x4)/(4+4)
3=(4x4-4)/4
4=(4x4)/((sqrt(4)+sqrt(4))

5=4+(4/4)^4
6=(4+4)/4+4
7=44/4-4
8=4-4+4+4
9=4+4+(4/4)
10=4+4+4-sqrt4
11=
12=4(4-4/4)
13=4!/sqrt(4)+4/4

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11 is open for a solution

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