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4x4

4x4

Posers and Puzzles

d

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10 Jun 07
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wait wait wait, if 44 isn't allowed, then my entry for 10 needs to be changed.

D

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(4squared -4)+(4/4)=13

R
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sqrt's aren't allowed?

C

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44 is OK. 4 squared is not (there is a 2 in squared) SQRT (4) is OK but not cube root (4) (as there is a 3). All 4's must be used, so 4+4+4=12 is no good.
Going well, but get back on track guys.

C

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And exactly FOUR 4's!

R
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but sqrt(4) = 4^1/2 there is a 2 (index)

C

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Originally posted by joe shmo
but sqrt(4) = 4^1/2 there is a 2 (index)
There is a common symbol for sqrt(x), and it doesn't use the 2. I know that the 2 is implied, but it's not actually there - so it is allowed.

C

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Up to 10 was OK.
44/(sqrt(4)*sqrt(4))=11

X

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(4*4)-sqrt(4)-sqrt(4) = 12

X

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44/4+sqrt(4) = 13

X

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4+4+4+sqrt(4) = 14

X

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4*4-(4/4) = 15
4+4+4+4 = 16

d

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4x4+4/4 = 17

k

Sigulda, Latvia

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Originally posted by Gastel
4^(4-4)*4 = 4[/b]
Wrong. 4^0=1; (4-4)*4=0

Correct. 4^1=4; 4^(4/4)=4^1=4

A
The 'edit'or

converging to it

Joined
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4+(4*4)-sqrt(4) = 18
4!-4-(4/4) = 19
(44-4)/sqrt(4) = 20
4!-4+(4/4) = 21

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