Mark,
Forgive my density, first of all.
If the square looks something like so:
----------------
|. . . . . . . . .|
|. . . . . . . . .|
|. . . . . . . . .|
|. . . . . . . . .|
----------------
(Sorry, had to get that offa my chest bro)
call the corners
----------------
|a . . . . . . .b|
|. . . . . . . . .|
|. . . . . . . . .|
|c . . . . . . .d|
----------------
the treasure is 2 units from a, three from b, and four from d, yes?
so, in that case,
----------------
|a . . . . . ./ b|
| . .\ . . / . . .|
| . . .\/(A) . . |
| . . . . .\ . . .|
|c . . . . . . \d|
----------------
__ . . . .__ . . . . . . . . . . .__
Aa = 2, Ab = 3, and Ad = 4
So m>aAb + m<dAb does not equal 180, and hence there is not a straight line formed from a to d, so right triangle geometry is right out. Dangit!
We then have two triangles, 2x3xX and 3x4xX
. . . . /\................/\
. . 2 / .\3......&...3/. \4
. . . /__1\ .......... /__2\
. . . . x . . . . . . . . x
where m<1 + m<2 = 90deg
Sorry, that's as far as I got in geometry. Told you y'all had to be the brains behind this operation! Couldst thou explain, esse?
Originally posted by milchcowThe treasure is always 2 miles from one corner and 4 miles from the opposite corner. So if the treasure is 4 miles from corner "b" it will always be 2 miles from corner "c"...
Mark,
Forgive my density, first of all.
If the square looks something like so:
----------------
|. . . . . . . . .|
|. . . . . . . . .|
|. . . . . . . . .|
|. . . . . . . . .|
----------------
(Sorry, had to ge ...[text shortened]... o be the brains behind this operation! Couldst thou explain, esse?
Otherwise you get a rectangle.
-------------
|a . . . . . .b|
|. . . . . . . .|
|. . . . . . . .|
|c . . . . . .d|
--------------
check out
http://www.riwire.com/images/1treasure.jpg
😉
Originally posted by milchcowDave! How great to see you back in here, albeit under a new handle. I don't think I have the patience to type too many squares. Read up on Hero's Theorem, and I'll explain this one to you over a cup of tea.
Mark,
Forgive my density, first of all.............Couldst thou explain, esse?
~Mark