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Originally posted by randompersonI would be surprised if this works at all... original poster says all should touch each other where in a hex center would only touch all others and each on outside would only touch 3 others..... I am no mathamatition (heck, I can't even spell it) but it sounds impossible to me.
can't u just fit them into a hexagon and let them be any size?
Originally posted by PhlabibitIt is definitely possible. I have drawn it, built it out of cigarettes, and solved the problem.
I would be surprised if this works at all... original poster says all should touch each other where in a hex center would only touch all others and each on outside would only touch 3 others..... I am no mathamatition (heck, I can't even spell it) but it sounds impossible to me.
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Originally posted by royalchickenYeah! I was starting to wonder that... but I can't see it... can it be done with pencils? Havn't tried but thought about it.😲
Phlabibit, they needn't all be placed "on a plane". Some of them can be standing up, stacked, etc.
wait... update.. If it can be done with cigarettes perhaps I can try it with golf pencils.
Another update. They are not on a plane, more like a weave around a center axis.... I may need some string for this....😲
Originally posted by royalchickenI used a CAD package to draw it out and measured the outcome (wrong) first based on the cylincers not quite reaching each other to touch at the center bottom and top planes of 3... and finally figured out I did it wrong and drew it again "more better"
Excellent work 😀! The answer is actually 7*sqrt(3)/2 =~ 6.07. Did you prove it?
Anyhow, I don't have the skill to do that with a pencil "math style". I basicly drew it and measured based on a Diameter of 1.
Originally posted by PhlabibitGood on you. The way to do it, "math style", would be to look at it in its limiting position and from there it is a matter of trigonometry. It's actually harder to prove it with 6 cylinders, where the minimum l/d=2*SQRT(3).
I used a CAD package to draw it out and measured the outcome (wrong) first based on the cylincers not quite reaching each other to touch at the center bottom and top planes of 3... and finally figured out I did it wrong and drew it again "more better"
Anyhow, I don't have the skill to do that with a pencil "math style". I basicly drew it and measured based on a Diameter of 1.
CAD-Very impressive 😀! I didn't see that coming.
Originally posted by royalchickenCool. If anyone cares to see the picture I placed it up at
Good on you. The way to do it, "math style", would be to look at it in its limiting position and from there it is a matter of trigonometry. It's actually harder to prove it with 6 cylinders, where the minimum l/d=2*SQRT(3).
CAD-Very impressive 😀! I didn't see that coming.
http://www.riwire.com/images/cylinder1.jpg
Nothing fancy like a 3d image, but shows the one cylinder on end and the other 6 in 2 groups of 3.😵
Originally posted by royalchickenIf you don't have an antique car you probably wouldn't care. We reproduce original style cloth covered wire sets for old cars like America's Big 3 from the mid to late 1950's and older (Ford / Chevy and Chrysler) as well as Studebaker, Packard, DeSoto, REO, Willy's, Bantam, Hudson, etc.
Very impressive drawing...what is "riwire"?
Lucas wiring (Jaguar's / Cobras / MG / Austin Healey / Astin Martin)
We do Mercedes (although Mercedes sells everything they ever made for a car from the factory for One arm and a leg)
Cars you may not remember like Tucker, Cord, Durant, and Essex etc.
Cars you never heard of like RV Knight, Seyers Scovil, Mercer, Jordan, etc.
It's fun as heck.
😛