Sorry I forgot about this
you are both still slightly wrong:
From the wikipedia entry on decagons:
Area of a regular decagon = 2.5dt where:
t = length of a side
d = distance between two parallel sides
they are related:
d = 2t(cos(54) + cos(18)) {angles in degrees}
so area_of_decagon = 5t^2(cos(54) + cos(18))
lets say the side is length one, then:
area 5(cos(54) + cos(18))
Now a decagon has 10 sides, and a square has 4, so there should be 2.5 decagagon sides between any two square corners. Draw a decagon.
Try setting a square corner to be a decagon corner,
now drawing corners at
2.5 side spacings we see that even though the sides are the
same length, the diagonals of the "square" are different lengths
so it isnt actually a square
Shunt every square corner round
by a quarter of a side, and we can see that all the diagonals
will now be the same, and the sides are the same, so its a square.
By pythagoras its easy to see that the length of a diagonal
of this square is
sqrt(d^2 + (t/2)^2)
where d and t are as above
the area of a square, in terms of its diagonal length is:
diagonal_length^2/2
so the area of the square is:
d^2/2 + t^2/8
recalling that d = 2t(cos(54) + cos(18)) {angles in degrees} and that t = 1
area_of_square = 2(cos(54) + cos(18))^2 + 1/8
so the ratio:
square_area/decagon_area
(2(cos(54) + cos(18))^2 + 1/8)/5(cos(54) + cos(18))
so the answer is:
0.6317826922466960