04 Jul 05
Originally posted by THUDandBLUNDERIs this possible? I cannot see how White can force Black to mate them /and in five moves no less!?/ or vice versa. Perhaps this is a helpmate problem?
In the position below
a) White to play and selfmate in 5, the final move being RxN mate.
b) Black to play and selfmate in 5, the final move being RxN mate.
[fen]rnbqkb1r/pppppp1p/N5p1/8/n7/1P6/P1PPPPPP/RNBQKB1R[/fen]
04 Jul 05
1 edit
Originally posted by THUDandBLUNDERI can hardly believe this
In the position below
a) White to play and selfmate in 5, the final move being RxN mate.
b) Black to play and selfmate in 5, the final move being RxN mate.
[fen]rnbqkb1r/pppppp1p/N5p1/8/n7/1P6/P1PPPPPP/RNBQKB1R[/fen]
edit: oops I was not the first to mention this
06 Jul 05
1 edit
Originally posted by marinakatombIt's a part of heterodox problems (helpmates and selfmates). In helpmates both sides cooperate to get the Black King (usually) mated; selfmate is when White forces Black to mate them (Black does not cooperate).
Please explain the rules, i don't know what help mate means officially. 🙂
Have a look here for more details:
http://www.chess.freegames.eu.com/problems-puzzles/helpmate.html
06 Jul 05
Originally posted by ilywrinGiven that, the poster of the puzzle should make it clear which side is going to be mated in a) resp. b).
It's a part of heterodox problems (helpmates and selfmates). In helpmates both sides cooperate to get the Black King (usually) mated; selfmate is when White forces Black to mate them (Black does not cooperate).
Have a look here for more details:
http://www.chess.freegames.eu.com/problems-puzzles/helpmate.html
06 Jul 05
1 edit
Originally posted by Mephisto2Although it is the convention with helpmates that Black moves first and is mated, there is no inherent reason why he should move first. However, this puzzle retains the convention that the side which moves first is mated.
Given that, the poster of the puzzle should make it clear which side is going to be mated in a) resp. b).
