Originally posted by royalchickenGood observation. I think can all agree that there is no such thing as "weak crabs."
When I can be bothered to write the next entry in the Companion Thread on Bayesian inference/weight of evidence at FW, I will use this example rather than God, because there are fewer objections to it.
Originally posted by royalchickenIt can be done using standard mathematical functions . (b) is reducible to the form of (a) and ( a) is integrable in terms of standard functions.
I can only reduce them to some complicated stuff times some funny integrals involving a; I can't get a complete expression for them in terms of elementary functions.
ALBERT EINSTEIN'S RIDDLE
1. In a street there are five houses, painted five different colors.
2. In each house lives a person of different nationality.
3. These five homeowners each drink a different kind of beverage, smoke a different brand of cigar and keep a different pet.
THE QUESTION: WHO OWNS THE FISH?
HINTS
1. The Brit lives in a red house.
2. The Swede keeps dogs as pets.
3. The Dane drinks tea.
4. The Green house is on the left of the White house.
5. The owner of the Green house drinks coffee.
6. The person who smokes Pall Mall rears birds.
7. The owner of the Yellow house smokes Dunhill.
8. The man living in the center house drinks milk.
9. The Norwegian lives in the first house.
10. The man who smokes Blends lives next to the one who keeps cats.
11. The man who keeps horses lives next to the man who smokes Dunhill.
12. The man who smokes Blue Master drinks beer.
13. The German smokes Prince.
14. The Norwegian lives next to the blue house.
15. The man who smokes Blends has a neighbor who drinks water.
Originally posted by geniusIt's actually Vedic Mathematics, an ancient gem of India:
99*91
=9100-91
=9009
i did it in about 5 though :'(
Multiply the unit's place of the multiplicand by that of the multiplier:
i.e. 9*1=9.
Prefix a 0 to that product 9 (There is a reason behind this, which you need not bother now)
Now, since 91 (multiplier) is 9 less than 100 (100 is considered as a base in vedic maths), you subtract the same deficit (9) from 99 (the multiplier), which is: 99-9=90.
There's your answer: 9009!
Originally posted by Brother Edwineasy:
You are on a games show,
there are 3 doors
behind one door is a car and behind the other doors are nothing
You choose a door at random
the gameshow host opens one of the doors which you have not picked and reveals it to be empty.
He says you may change your choice to un opened door or stay with your original choice.
should you stay with your choice, change door or dosent it matter?[/b]
1/3 chance of it being in the one you chose, call it A.
2/3 chance of it being in B or C.
He opens up B, empty
therefore there is now a 2/3 chance of it being in C.
Definately switch!!!
1/3 chance by staying with it, 2/3 chance by switching.