In that case, I believe both your probabilities are zero. There are an infinite number of positions of the hands (because they move smoothly) and a finite number (c) of those hand positions will be isoceles or right angled triangles, therefore the probability that the clock is in one of those positions when you look at it is
c/infinity = 0.
Originally posted by iamatigerExcept that THUDandBLUNDER said, 'given that the triangle has integer length sides', so there are problems defining the relevant random variables.
In that case, I believe both your probabilities are zero. There are an infinite number of positions of the hands (because they move smoothly) and a finite number (c) of those hand positions will be isoceles or right angled triangles, therefore the probability that the clock is in one of those positions when you look at it is
c/infinity = 0.
Here's a good one:
Given a normal clock, where the second hand moves in full seconds, the minute hand in 60/th of a minute etc. If the hour hand is 3 cm long, and the minute hand is 4 cm long, at how many times during 12 hours are the tips of the hands separated exactly by an integral number of cm?