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belgianfreak
stitching you up

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Originally posted by Fiathahel
But then AD/DB * BE/EC * CF/FA =/= 1 .
(I notice now I mistyped CF/FA the first time)

aaargh, more maths!!!!

F
Artist in Drawing

in your fridge

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Originally posted by belgianfreak
aaargh, more maths!!!!
Sorry, I forgot this was a "no math" Thread. It won't happen again 🙂

belgianfreak
stitching you up

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Originally posted by Fiathahel
Sorry, I forgot this was a "no math" Thread. It won't happen again 🙂
he he he 🙂 no problem here - except that the maths puzzles make my brain liquify and attempt to escape out of my left ear 😉

iamatiger

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Originally posted by richjohnson
I don't think that's true in the general case. If D's near B, E's near C and F's near A, then AE and CD intersect near C, and AE and BF intersect near A.
If D's near B, E's near C and F's Near A: Then BF, AE and CD don't intersect at one point. The general proof is still possible 😉

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