Question about energy at one wavelength:

Originally posted by sonhouse
I simplified the constant, to just 4G/c^2 which is 2.973E-27. Then all you have to do to figure the deflection for any body is to do M/r and multiply that by my new constant, I call Z. Any star, Z*M/r, M in Kg, r in meters = deflection angle in radians. Assuming you know M and r that is.

Your K for Sirius is 11951 btw.

So using my new constant, Z ( ...[text shortened]... t Sirius.

What do you think? Numbers ok? What do you think of my new constant Z=2.973 E-27 ?

I've done this for Sirius A and B now. I get the following results:

Luminance of Sun at Sirius = 4.62 E-9 W/m^2

Sirius A:
Radius Sirius A = 1.711 solar radii
Mass Sirius A = 2.02 solar masses
K Sirius A = 11931 metres
Angle of deflection = 2.06 arc seconds
Point of first focus = 794 AUs
Area Annulus = 3,739,571,877 m^2
Power from Sun through annulus at Sirius A = 17.29 Watts
Irradiance of 1m collector disk at first focus by Sirius A = 0.17 Watts
ratio Sun/Sirius at Sirius A first focus = 99.8

Sirius B:
Radius Sirius B = 0.0084 solar radii
Mass Sirius B = 0.978 solar masses
K Sirius B = 5777 metres
Angle of deflection = 203 arc seconds
Point of first focus = 0.040 AUs
Area Annulus = 18,359,090 m^2
Power from Sun through annulus at Sirius B = 0.085 Watts
Irradiance of 1m collector disk at first focus by Sirius B = 148609 Watts (Due to much greater proximity of 1st focus point)
ratio Sun/Sirius B at Sirius B first focus = 5.71E-7

To recap the corresponding figures for the Sun are:
Radius Sun = 1 solar radius
Mass Sun = 1 solar mass
K Sun = 5907 metres
Angle of deflection = 1.75 arc seconds
Point of first focus = 548 AUs
Area Annulus = 2.185606E+009 m^2
Power from Sirius through annulus at Sun = 257 Watts
Irradiance of 1m collector disk at first focus by Sun = 0.0047 Watts
ratio Sirius/Sun at first focus = 17,550

We differ by 10% on the deflection at Sirius B, but apart from that it all looks similar.

Originally posted by DeepThought
I don't think your statement that there's much greater radiation at the focal point is correct. My reason for thinking this is that the radius of the annulus is vastly smaller so less radiation will reach the collector. I'll check all the figures and confirm that.

It would seem your figures confirm my statement.

Originally posted by twhitehead
It would seem your figures confirm my statement.

Were you talking about the direct radiation from Sirius B (in which case yes) or the focused radiation from the Sun (in which case no)?

Originally posted by DeepThought
Were you talking about the direct radiation from Sirius B (in which case yes) or the focused radiation from the Sun (in which case no)?

I read it wrong. The results are interesting. I really need to work out the general formula and draw some graphs.