Originally posted by clandarkfireYou might want to consider other ways to give a hint
Ok, I'll give you a hint. 1.B c7-e5
Will the pawn promote?
If so, on which square?
If so, what should it (not) become?
Are all the bishops important?
Is zugzwang a motive?
Is there only one solution?
Answering one (or more if necessary) of those questions would be a hint. Just giving away the first move doesn't feel right.
Originally posted by Drew LAll true, but then there are many extremely elegant puzzles that are still interesting to solve but don't have any real chance of ever being seen in a real game.
I have a question : what is with all the dang bishops. If I had the oppertunity in a game to promote three pawns the last thing I would get is three bishops. I tell you what, I would have ended that game awhile ago with a couple queens. 😀
This puzzle would certainly be categorized as one of those. Not only are there so many bishops, but somehow they all ended up on the same color as well. Pretty unlikely, but still interesting.
I still don't see how there is a forced win for this puzzle. I see how it could be won, but it seems to require some cooperation on Black's part.
Originally posted by TippedKingWRONG!
All true, but then there are many extremely elegant puzzles that are still interesting to solve but don't have any real chance of ever being seen in a real game.
This puzzle would certainly be categorized as one of those. Not only are there so many bishops, but somehow they all ended up on the same color as well. Pretty unlikely, but still interestin ...[text shortened]... puzzle. I see how it could be won, but it seems to require some cooperation on Black's part.
1 Bc7-e5 P-a5
2 Be5-a1 p-a4
3 Bb8-e5 p-a3
4 K-d2 k-a2
5 K-c3 kxa1
6 K-b3+ k-b1
7 B-a1 p-a2
8 K-c3 kxa1
9 Kc2#
(And if 5...K-b1, 6 K-b3 P-a2 7 K-c3 Kxa1 8 Kc2#
And
1 Bc7-e5 K-a2
2 K-c2 P-a5
3 Be5-a1 P-a4
4 K-d2 P-a3
5 K-c3 Kxa1
5 K-c2#
😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀
Originally posted by clandarkfireIn the first line, how does white continue if instead of 4..k-a2 black plays 4..P-a2?
WRONG!
1 Bc7-e5 P-a5
2 Be5-a1 p-a4
3 Bb8-e5 p-a3
4 K-d2 k-a2
5 K-c3 kxa1
6 K-b3+ k-b1
7 B-a1 p-a2
8 K-c3 kxa1
9 Kc2#
(And if 5...K-b1, 6 K-b3 P-a2 7 K-c3 Kxa1 8 Kc2#
And
1 Bc7-e5 K-a2
2 K-c2 P-a5
3 Be5-a1 P-a4
4 K-d2 P-a3
5 K-c3 Kxa1
5 K-c2#
😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀
Originally posted by clandarkfireAfter 4.Kd2 the black king can escape with Kb3 followed by a3 and Ka4.
WRONG!
And
1 Bc7-e5 K-a2
2 K-c2 P-a5
3 Be5-a1 P-a4
4 K-d2 P-a3
5 K-c3 Kxa1
5 K-c2#
😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀
Surely you meant 4.Bbe5! a3 5.Kc3 Ka1: 6.Kb3+ Kb1 7.Ba1 a2 8.Kc3 followed by checkmate as we know it?
Originally posted by kbaumenCan I get in on this bet. 🙂
It's a draw. There is no possible mating pattern with no matter how much single-color-squared bishops.
Originally posted by clandarkfire
I'll bet you $1000
Just kidding. But kbaumen is right, there is no way to mate. If black plays it perfectly. Explain your solution so that someone here can explain why you're wrong.Then if you still want to give me that $1,000..... 🙂
-- Paul
Originally posted by clandarkfireYour first solution i don't think can be forced though. What if black decides not to move his pawn at all after it reaches a3; but only stay on the white squares?
[fen]1B3B1B/2B5/p6B/8/8/8/8/1k1K4 w - - 0 99[/fen]WRONG!
1 Bc7-e5 P-a5
2 Be5-a1 p-a4
3 Bb8-e5 p-a3
4 K-d2 k-a2
5 K-c3 kxa1
6 K-b3+ k-b1
7 B-a1 p-a2
8 K-c3 kxa1
9 Kc2#
(And if 5...K-b1, 6 K-b3 P-a2 7 K-c3 Kxa1 8 Kc2#
And
1 Bc7-e5 K-a2
2 K-c2 P-a5
3 Be5-a1 P-a4
4 K-d2 P-a3
5 K-c3 Kxa1
5 K-c2#
😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀😀
This is how the end of your second solution to the puzzle looks:
Is not checkmate 'cause King still has a2. And if white doesn't move after king a2 then stalemate.