2+2=5

The funny thing with the decimal positional system is that you can often (not always) write the same number in two ways.

0.99999... = 1
0.2499999... = 0.25
etc.

This is not a flaw, it is a property.

Originally posted by EinsteinMind
This convention will not work when x is any negative integer. for instance, the two square roots of -1 are indeed i and -i. These cannot be distinguished on the basis of "positive" and "negative"; so how do we know which one is being meant by SQRT -1?

Therefore this step of the proof may seem unclear.

HOwever, this can be easily remedied.

Just ...[text shortened]... ative multiple of i."

It simply rationalizes away by defining which SQRT you are after.

Originally posted by doodinthemood
This is generally to do with rounding:
2.4 rounds to 2
2.4+2.4=4.8 which rounds to 5.

If you round everything: 2+2=5

Originally posted by rubberjaw30
premature rounding not allowed in mathematics and is not given any credit on AP Exams

Originally posted by Doctor Rat
If there is a general formula involved in the proof, make sure division by zero isn't happening because that isn't allowed. So for example the classic case of the fallacy of 1=2 (which is very similar to yours)
step 1
[b]Let a = b
step 2 Multiply both sides by a:
aa = ab
step 3 which is the same as:
a^2 = ...[text shortened]... oof of 2+2=5.

(sorry for all the edits, but I had to work out some formatting issues)

Originally posted by jenna1
i'm seriously confused now...

step 1
Let a = b
step 2 Multiply both sides by a:
aa = ab
step 3 which is the same as:
a^2 = ab ( "a squared equals a times b" )
step 4 Add the quantity ( a^2 - 2ab) to both sides:
a^2 + (a^2 - 2ab) = ab + (a^2 - 2ab)
step 5 simplifying both sides we get:
(a^2 + a^2) - 2ab = a^2 + (ab - 2ab)
2(a^2) - 2ab = a^2 - ab
2 (a^2 - ab) = a^2 - ab
step 6 divide both sides by (a^2 - ab):
2(a^2 ...[text shortened]... ab) / (a^2 - ab) = (a^2 - ab) / (a^2 -ab)
step 7 cancel out like terms in num.&denom:
2 = 1 !!!

Originally posted by EinsteinMind
Wrong. It's a mistake, but an asusmption or a definition of which SQRT you are after, and the problem continues.

Originally posted by eatmybishop
tell me in what way that is wrong and i'll back down.... i sense you know you've lost....

here's the quote on binary numeral system...

could you actually read the whole thread then get back to me... if you have trouble understanding it send me a message and i'll explain it to you...

it is them who have converted the answer to decimal... 10 + 10 ur; it is not, its value remains 10"

is this wrong too????

apology accepted loser

Originally posted by lausey
You will find that computers wouldn't convert to decimal, do the addition, and then convert back to binary. Decimal is only for us to easily understand, which is base 10 (ten) numbers. Binary are base two numbers which is what computers do arithmetic in because it can only handle two states.

Therefore, as far as computers is concerned, 1 + 1 = 0 (wi ...[text shortened]... hich is something completely different.

0 AND 0 = 0
1 AND 0 = 0
0 AND 1 = 0
1 AND 1 = 1

Originally posted by eatmybishop
your boolean algebra is incorrect..

Originally posted by Palynka
Wrong.

bet you wanna go hide now mr panda killer

Originally posted by eatmybishop
it was actually me who said a computer will not convert to decimal... they were saying it would....

with all respect, your boolean algebra is incorrect.. it should read...

0 + 0 = 0
1 + 0 = 1
0 + 1 = 1
1 + 1 = 1

hope this helps

Originally posted by SwissGambit
Everything you post about binary is wrong. Just stop.