24 Sep 07
Originally posted by eatmybishopI have just read this entire thread. I'm no mathemetician, but this post is just about the most absurd thing I have ever read. I think the average fourth grader understands binary numbers better than this.
no its not, you're wrong...
i was under the impression is was binary to decimal.. so you're right there, there is no 4 or 256 in binary... however you're still wrong...
in binary, it would be 10+10=10... you are wrong to say 100, its not, 1 + 1 = 1 or 0 + 1 = 1, 0 + 0 = 0.... there is no additional digit.... mr dumb!
26 Sep 07
Originally posted by Maxwell SmartI'm an educator, and believe me, the average fourth grader has never heard the word binary before.
I have just read this entire thread. I'm no mathemetician, but this post is just about the most absurd thing I have ever read. I think the average fourth grader understands binary numbers better than this.
27 Sep 07
Originally posted by Maxwell SmartI got the point in the first place. Your sarcastic joke was just...bad.
The source that I quoted obviously had no understanding of binary numbers. The point was abundantly obvious. I spelled it out because you were clearly having problems with it. Cheers.
It's like...
"Dude! That box is HEAVY! Even a paraplegic couldn't pick THAT thing up!"
It just doesn't make sense...
27 Sep 07
Originally posted by AThousandYoungHowever, the average fourth grader would probably be able to understand it a lot more quickly than eatmybishop if it were explained to them (eatmybishop would probably also have been able to understand it a lot more quickly if he'd be less stubborn). We learned binary in fifth grade, and I don't think the average student had any trouble to grasp the concept.
I'm an educator, and believe me, the average fourth grader has never heard the word binary before.
01 Oct 07
Originally posted by wolfgang59that may be one way and yes i meant recurring. anyways this is my solution:
You mean .9 recurring = 1 yes?
let X= 0.999999 .....
then 10X = 9.99999999 .....
X = 0.99999999 ....
subtract
therefore 10X - X = 9
therefore 9X = 9
therefore X = 1 QED
1/3= 0.3333333...
2/3=0.6666666....
--------------------
3/3=0.9999999....
its very rough but thats the way i found it. im sure you guys no that 3/3 is 1 otherwise this thread wouldnt be here.
01 Oct 07
Originally posted by tournymangrOr in the tersiary system
that may be one way and yes i meant recurring. anyways this is my solution:
1/3= 0.3333333...
2/3=0.6666666....
--------------------
3/3=0.9999999....
its very rough but thats the way i found it. im sure you guys no that 3/3 is 1 otherwise this thread wouldnt be here.
0.1
0.2
1.0
The fact is that when you calculate in thirds and ninths and 1/(3^n) the calculations become very much simpler than in the usual decimal system.
01 Oct 07
Originally posted by tournymangrYou have started with the assumption that 1/3 = 0.3333... which was not given.
that may be one way and yes i meant recurring. anyways this is my solution:
1/3= 0.3333333...
2/3=0.6666666....
--------------------
3/3=0.9999999....
its very rough but thats the way i found it. im sure you guys no that 3/3 is 1 otherwise this thread wouldnt be here.
(Prove that 0.333 .... = 1/3 !)
01 Oct 07
Originally posted by wolfgang59But this was not an assumption, it's a fact, and can easily be proven:
You have started with the assumption that 1/3 = 0.3333... which was not given.
(Prove that 0.333 .... = 1/3 !)
Let x = 0.33333...
Then 10x = 3.33333...
Subtraction gives that 10x-x = 9x = 3.33333... - 0.33333... = 3
And if 9x = 3 then x must be 3/9 = 1/3 and that's the proof.
Every decimal number with a repetetive decimals can be written as p/q with p and q are integers.