09 Nov 04
Aren't you folks interested in finding out the trick ?
I wish I hadn't used that word "trick" as I realise it made you all paranoid.
I really do need a large group of people it to work. It also means that I get to broadcast my discovery simultaneously to as many people as possible and thus reduce the chances of someone else claiming it as their discovery.
Maybe, I'll just let it go.
09 Nov 04
Originally posted by STANGHow about you just tell us the next step, and then things will either work or not work depending on how many people have thought of a number? Even if it doesn't work we ought to be able to imagine how it might work given more people.
Aren't you folks interested in finding out the trick ?
I wish I hadn't used that word "trick" as I realise it made you all paranoid.
I really do need a large group of people it to work. It also means that I get to broadcast my discovery simultaneously to as many people as possible and thus reduce the chances of someone else claiming it as their discovery.
Maybe, I'll just let it go.
09 Nov 04
Originally posted by AcolyteOK.
How about you just tell us the next step, and then things will either work or not work depending on how many people have thought of a number? Even if it doesn't work we ought to be able to imagine how it might work given more people.
Calculate the sum of the digits in your number.
Then click on the RECOMMEND button at the top of this thread.
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10 Nov 04
1 edit
Let's guess what it could be:
Take a number of 2 or more digits
calculate the sum of the digits and take that sum away from the original number
sum the digits of the answer
if the digit sum has more than 1 digits then sum it's digits, and continue doing that repeatedly until you have a 1 digit answer
your answer is 9.
10 Nov 04
Originally posted by iamatigerthere are a number of known add-the-didget number tricks, most of the ones i've seen produce loops, not a single answer. i've never seen a proof of one, but i've never looked
Let's guess what it could be:
Take a number of 2 or more digits
calculate the sum of the digits and take that sum away from the original number
sum the digits of the answer
if the digit sum has more than 1 digits then sum it's digits, and continue doing that repeatedly until you have a 1 digit answer
your answer is 9.
10 Nov 04
1 edit
Originally posted by jimmyb270Anyone can by now guess his trick for certain. I, for example KNOW his trick . I will reveal it to all of you ...in my next post...In the meantime give me 20 recs.....OKAY.?.I need the recs because I want a larger number of people to KNOW this miraculous TRICK.....
Why do you need recs? WIll this trick not work without them?
10 Nov 04
2 edits
Originally posted by iamatigerYes Iamatigre, Your contention can be proved to be true according to simple rules of arithmetic....BUT,.this does not sound to be that great a secret as STANG wants us to believe his trick must be..
Let's guess what it could be:
Take a number of 2 or more digits
calculate the sum of the digits and take that sum away from the original number
sum the digits of the answer
if the digit sum has more than 1 digits then sum [i]it' ...[text shortened]... t repeatedly until you have a 1 digit answer
your answer is 9.
He wants us to believe that his trick, has remained unproven and unprovable by mathematics, something deeper and much more profound .
If at all his trick is something other than accumulating a record number of recs exploiting the curiousity of all the respondents of this thread..., .it should be taken with all seriousness..
10 Nov 04
Originally posted by STANGBut why do you need the recs? Do you want the recs as a price for revealing the trick? Does this not amount to exploiting the curiousity of
The next step is to square the answer you got when you added up the digits. Without any more recs, that's as far as I'm going to go.
posters to accumulate recs for yourself?