Originally posted by chasparosSince nobody else is trying, here is my attempt:
ok.. This is a bit diffrent... (and maybe not that difficult)
W: Ka1 b6 d2
B: Ka3 b3 d3 a6
Black to play..
White pawn is unstoppable, but can you show the white win?
1. ... b3+
The first two moves by black are interchangable. Black's kingdoes not move because the white king would immediately come to b2.
2.Kb1 a5
3.b7 a4
4.b8N!
promotion to queen or rook would be stalemate. Promotion to bishop would not win.
4. ... Kb3 (needs to protect the pawn)
5.Nd7 a3
6.Nc4+ Kc4 (or Kb4)
7.Ne4 Kb3
8.Nc3 followed by 9.Ka2, 10.Nb1 and 11.Nxa3 wand later on also the other two pawns.
Originally posted by Mephisto2Yes, that right...
Since nobody else is trying, here is my attempt:
1. ... b3+
The first two moves by black are interchangable. Black's kingdoes not move because the white king would immediately come to b2.
2.Kb1 a5
3.b7 a4
4.b8N!
promotion to q ...[text shortened]... 9.Ka2, 10.Nb1 and 11.Nxa3 wand later on also the other two pawns.
Wasnt so hard, but a nice example of underpromoting :-)
I'll try to find a harder one :-)
I sort of liked the position tho...
Originally posted by yamiyokazeok Ill hav a half go :-) ... white line:
Okay...here's an interesting problem:
White: Kg2, Qe8, Rf2, Rh2, Nc5, Nf5, Bc4, Bg3.
Black: Kc2, Qg4, Rb2, Rd2, Nd5, Ng5, Bc3, Be6, e7
White moves and mates in 5, or Black moves and mates in 5.
Try this on for size! ^_____^;;;
1. Qa4+ Kc1
2. Rh1+ Qd1
3. Qxd1+ Rxd1
4. Nd3+ Kb1
5. Rd1#
1. ... Rb3 2. Qxb3+ Kc2 3. Nd3+ Rxd3 4. Qc2#
1. ... Kb1 2. Rh1+ Qd1 3. Rxd1+ Rxd1 4. Qxd1#
Black line seens more difficult....
Originally posted by chasparosHow about:
ok Ill hav a half go :-) ... white line:
1. Qa4+ Kc1
2. Rh1+ Qd1
3. Qxd1+ Rxd1
4. Nd3+ Kb1
5. Rd1#
1. ... Rb3 2. Qxb3+ Kc2 3. Nd3+ Rxd3 4. Qc2#
1. ... Kb1 2. Rh1+ Qd1 3. Rxd1+ Rxd1 4. Qxd1#
Black line seens more difficult....
1. ... Rxf2+ 2.Kxf2
(2.Kg1 or 2.Kh1 then Rb1+)
2. ... Kb1+ 3.Kg1
(3.Be2 Qxe2+ 4.Kg1 Nf3+ 5.Kh1 Qf1π
(3.Kf1 Qd1+ 4.Be1 Qxe1π
3. ... Qd1+ 4.Bf1
(4.Be1 Nf3+ 5.Kh1 (5.Kf1 Qe1π Rxh2#
4. ... Nf3+ 5.Kh1 Qf1#.
Originally posted by Mephisto2Lol...
How about:
1. ... Rxf2+ 2.Kxf2
(2.Kg1 or 2.Kh1 then Rb1+)
2. ... Kb1+ 3.Kg1
(3.Be2 Qxe2+ 4.Kg1 Nf3+ 5.Kh1 Qf1π
(3.Kf1 Qd1+ 4.Be1 Qxe1π
3. ... Qd1+ 4.Bf1
(4.Be1 Nf3+ 5.Kh1 (5.Kf1 Qe1π Rxh2#
4. ... Nf3+ 5.Kh1 Qf1#.
Seems to work just fine....
I can't tell how many times I tried 1. ... Rxf2+ 2. Kg1
and got it to six or seven moves....
After you posted this solution I tried it again.. Mate in three :-)
nice thinking on my part... NOT! :-)
Originally posted by asassinIf black takes the pawn, can you show how white gets fast a queen and wins the game .... in 11 or less moves? Please show that. I can't do it.
It can be done, black would not take the pawn, look deeper into the position. If black took back it would just allow white to get a fast queen and win the game. 1.b6+ then what?
Originally posted by asassinBut your puzzle stated mate in 11. Mate in 12 is not good enough.
Ok if black takes back mate in 12 1.b6 kxb6 2.h4 a5 3.h5 kb5 4.kc7 a4 5.kxb7 kb4 6. H6 a3 7.h7 kb3 8. h8=Q a2 9.kb6 ka3 10.Qc3 ka4 11. kc5 (black has no other move but to promote) a1=Q 12.Qb4#. Try another move for black.
The line that you give after Kxb6 is not black's only defense. I think that 2 . ... Kc5 gives black many more moves than 11 to survive.
But even after 1. b6+ Kb8, can you show that white mates in 11?